Simplifying and Evaluating Polynomials with More Than One Term
Learning Objective(s)
· Evaluate a polynomial for given values of each variable.
· Simplify polynomials by collecting like terms.
Introduction
You have studied polynomials consisting of constants and/or variables combined by addition or subtraction. The variables may include exponents. The examples so far have been limited to expressions such as 5x4 + 3x3 – 6x2 + 2x containing one variable, but polynomials can also contain multiple variables. An example of a polynomial with two variables is 4x2y – 2xy2 + x – 7.
Many formulas are polynomials with more than one variable, such as the formula for the surface area of a rectangular prism: 2ab + 2bc + 2ac, where a, b, and c are the lengths of the three sides. By substituting in the values of the lengths, you can determine the value of the surface area. By applying the same principles for polynomials with one variable, you can evaluate or combine like terms in polynomials with more than one variable.
When you evaluate an expression for a given value, you substitute that given value in the expression, and find its numerical value. In the following example, x = −2, you replace all of the x’s with a value of −2 and simplify the expression following the order of operations.
Example | ||
Problem | Evaluate 7x2 – 3x + 2 for x = −2. | |
| 7(−2)2 – 3(−2) + 2 | Substitute (−2) for each x in the polynomial. |
| 7(4) – 3(−2) + 2 | Following the order of operations, evaluate exponents first. |
| 28 + 6 + 2 | Perform the multiplication next. |
| 34 + 2 | Combine terms beginning from the left. |
Answer | 36 | Find the sum. |
You can follow the same procedure when there are two variables in an expression. Let’s look at an example.
Example | ||
Problem | Evaluate 8c – 7b for b = 4 and c = 5. | |
| 8(5) – 7(4) | Substitute 5 for each c in the polynomial and 4 for each b. |
| 40 – 28 | Multiply. |
| 12 | Find the difference. |
Answer | 12 |
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As with polynomials with one variable, you must pay attention to the rules of exponents and the order of operations so that you correctly evaluate an expression with two or more variables.
Example | ||
Problem | Evaluate x2 + 3y3 for x = 7 and y = −2. | |
| (7)2 + 3(−2)3 | Substitute the given values for x and y. |
| 49 + 3(−8) | Evaluate the exponents first. |
| 49 + (−24) | Multiply. |
| 25 | Add. |
Answer | 25 |
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Example | ||
Problem | Evaluate 4x2y – 2xy2 + x – 7 for x = 3 and y = −1. | |
4(32)(−1) – 2(3)(−1)2 + 3 – 7 | Substitute the given values for x and y. | |
4(9)(−1) – 2(3)(1) + 3 – 7 | Evaluate the exponents first. | |
| −36 – 6 + 3 – 7 | Perform multiplication next. |
| −42 + 3 – 7 −39 – 7 | Perform addition and subtraction from left to right. |
Answer | −46 | Find the difference. |
The next example shows how to evaluate a polynomial with two variables. This polynomial is the formula for perimeter of a rectangle.
Example | ||
Problem | The formula for the perimeter, P, of a rectangle is 2a + 2b in which a and b are the lengths of the sides of the rectangle. Evaluate the formula for a = 6 inches and b = 10 inches. | |
| 2(6) + 2(10) | Substitute the given values for a and b. |
| 12 + 20 | Multiply. |
Answer | 32 | Add. |
Evaluate 2x3 – xy2 + 6 for x = −2 and y = 5
A) −158
B) −60
C) 14
D) 40
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Identifying the Degree of a Polynomial with Two or More Variables
Mathematicians use conventions for writing and describing polynomials. A polynomial with one variable can be described by the number of terms it has and the degree of the term with the greatest exponent. Polynomials are commonly written with their terms in descending order of degree. Let’s start by looking at an example of a polynomial with one variable: t3 – 10t2 – 5t – 32. This polynomial has been written in descending order of degree, starting with the term with an exponent of 3 and ending with the term whose degree is 0 because it has no variable. This polynomial is called a third degree polynomial because its term with the highest degree is the monomial t3. (Note that the degree of a monomial, t3, is also 3, because the variable t has an exponent of 3.)
When a polynomial has more than one variable, you can still describe it according to its degree and the degree of its terms. It’s a little more complicated. Let’s look at a polynomial with two variables: 7x2y – 3xy3 + 2x. This polynomial has three terms and therefore can be called a trinomial. To determine the degree of a term, you find the sum of the exponents of all the variables in the term.
Terms | Sum of the Exponents | Degree of the Term |
7x2y | 2 + 1 = 3 | 3 |
−3xy3 | 1 + 3 = 4 | 4 |
2x | 1 = 1 | 1 |
The degree of a polynomial is the same as the degree of the term with the highest degree. In this case, 7x2y – 3xy3 + 2x is a fourth degree polynomial.
What description below best matches the expression: 2x4y – 5x3 – 10xy3?
A) A twelfth degree trinomial
B) A fifth degree trinomial
C) A third degree polynomial
D) A fourth degree polynomial
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If a polynomial has like terms the polynomial can be simplified by combining the like terms.
You’ll recall that like terms contain the same exact variables raised to the same exact power. If there is more than one variable, the same is true – same exact variable(s) each raised to the same exact power.
The polynomial 3xy3z2 + 5xy3z2 + 6x2y3z has like terms that can be combined. 3xy3z2 and 5xy3z2 are like terms because they have the same exact variables, x, y, and z, raised to the same exact powers, x, y3, and z2. They can be collected, or combined, to give a result of 8xy3z2. Notice that while 6x2y3z has the same variables, x, y, and z, the exponents in this term are different, x2 instead of x, and z instead of z2. So, 6x2y3z cannot be combined with the other terms. Instead, the simplified polynomial is written with two terms: 8xy3z2 + 6x2y3z.
Example | ||
Problem | Simplify 2xy2 – 8x – 3xy2 + 3x. | |
| 2xy2 – 8x – 3xy2 + 3x | Identify any like terms. |
| 2xy2 – 3xy2 – 8x + 3x (2 – 3)xy2 + (−8 + 3)x −1xy2 + (− 5)x | Combine like terms using the distributive property. |
| −1xy2 – 5x | Rewrite using subtraction, and check to make sure all like terms have been combined. |
Answer | 2xy2 – 8x – 3xy2 + 3x = −xy2 – 5x |
Like with polynomials with one variable, you can combine like terms in polynomials with more than one variable by combining the coefficients of those like terms and keeping the variable part the same. That step is written in the example below. But to save time, you can also just perform the computation in your head.
Example | |||
Problem | Simplify 5ba2 + 3a2 + a2b – 4a2 – 2ab2. | ||
| 5ba2 + 3a2 + a2b – 4a2 – 2ab2 | Identify the like terms in the polynomial. Since 5ba2 can also be written 5a2b, it is a like term to a2b. | |
| (5 + 1)a2b + (3 – 4)a2 – 2ab2 6a2b – a2 – 2ab2 | Combine like terms using the distributive property and check to make sure all like terms have been combined. | |
Answer | 5ba2 + 3a2 + a2b – 4a2 – 2ab2 = 6a2b – a2 – 2ab2 | ||
Simplify by collecting like terms: 4(x2y + 7y) – 5y(3x2 – y) – 10y
A) −11x2y + 5y2 + 18y
B) 4x2y + 11y – 8yx2 – 16y
C) 4x2y + 18y – 15yx2 + 5y2
D) 4x2y – 5y(3x2 – y) – 3y
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Summary
Polynomials can contain more than one variable and can be evaluated in the same way as polynomials with one variable. To evaluate any polynomial, you substitute the given values for the variable and perform the computation to simplify the polynomial to a numerical value. The order of operations and integer operations must be properly applied to correctly evaluate a polynomial.
Polynomials with more than one variable can be simplified by combining like terms, as you can do with polynomials with one variable. Like terms must contain the same exact variables raised to the same exact power. In terms with more than one variable, the order in which the variables are written does not matter.